Invalid input 'EOI'

This doesn't work, why?

value = "ok"
if type(value) == "string" then
	print(value)
else
	value()

You need an "end".  See:

http://www.lua.org/manual/5.2/manual.html#9

You are right. It was my first if with else block, so I forgot the "end". But the error message is horrible. What is EOI? END OF IF? Please make this message more intuitive.

I posted about this to the parboiled users forum.

http://users.parboiled.org/Parse-Error-Handling-tp4024153.html

I will wait for an answer.

http://users.parboiled.org/Parse-Error-Handling-tp4024153p4024154.html

It looks like it will be a while before I can improve parse error messages.  You can assign this back to me at priority 2.

Okay, we can wait while users are not allowed to tweak luan. The error messages are horrible at this point, but I can live with that for the next months.

This is fixed.

Please check this and close it.

It looks better now. Closing thread.